rest vs drop

unsorted — cgrand, 23 February 2009 @ 18 h 20 min

Now that fully lazy sequences are in the trunk, (rest a-seq) and (drop 1 a-seq) aren’t equivalent anymore:

user=> (def s (map #(do (println %) %) (range 10)))
#'user/s
user=> (def d (drop 1 s))
#'user/d
user=> (def r (rest s))
0
#'user/r

As one can see rest needs to realize the first element of s while drop doesn’t. The corollary is that (drop n s) holds on the whole seq (including the nth first elements) while rest computes the first element and then discards it.

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